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How can we calculate the horizontal winner in a game of tic-tac-toe using a "not match" flag?

by EITCA Academy / Thursday, 03 August 2023 / Published in Computer Programming, EITC/CP/PPF Python Programming Fundamentals, Advancing in Python, Calculating horizontal winner, Examination review

To calculate the horizontal winner in a game of tic-tac-toe using a "not match" flag, we need to analyze the game board and check if any row has all the same symbols. In Python, we can achieve this by iterating over each row and comparing the symbols.

First, let's assume that the tic-tac-toe game board is represented as a 2D list, where each element corresponds to a cell on the board. For example:

python
board = [['X', 'O', 'X'],
         ['O', 'O', 'O'],
         ['X', 'X', '']]

To calculate the horizontal winner, we can define a function that takes the game board as input and returns the winning symbol (if any). Here's an implementation that uses a "not match" flag:

python
def calculate_horizontal_winner(board):
    for row in board:
        not_match = False
        if row[0] != '':
            for i in range(1, len(row)):
                if row[i] != row[0]:
                    not_match = True
                    break
            if not not_match:
                return row[0]
    return None

In this function, we iterate over each row in the board. For each row, we initialize the "not match" flag to False. If the first element of the row is not an empty string (indicating that the cell is not empty), we compare it with each subsequent element in the row. If any element is different, we set the "not match" flag to True and break out of the inner loop. If the "not match" flag remains False after the inner loop, it means that all elements in the row are the same, indicating a horizontal winner. In this case, we return the winning symbol.

If no horizontal winner is found after iterating over all rows, we return None to indicate that there is no winner.

Let's test the function with the example board mentioned earlier:

python
board = [['X', 'O', 'X'],
         ['O', 'O', 'O'],
         ['X', 'X', '']]

winner = calculate_horizontal_winner(board)
print(winner)  # Output: O

In this example, the second row contains all 'O' symbols, so the function correctly identifies 'O' as the horizontal winner.

This approach allows us to calculate the horizontal winner in a tic-tac-toe game using a "not match" flag. By iterating over each row and comparing the symbols, we can determine if any row has all the same symbols, indicating a horizontal winner.

Other recent questions and answers regarding Examination review:

  • What is the more efficient and concise solution for calculating the horizontal winner in tic-tac-toe using the "count" method in Python?
  • What improvement can be made to the code for calculating the horizontal winner in tic-tac-toe using the "all match" variable?
  • What is the advantage of using a dynamic approach to handle the winning conditions in tic-tac-toe?
  • How can we determine the winner in a game of tic-tac-toe using Python programming?

More questions and answers:

  • Field: Computer Programming
  • Programme: EITC/CP/PPF Python Programming Fundamentals (go to the certification programme)
  • Lesson: Advancing in Python (go to related lesson)
  • Topic: Calculating horizontal winner (go to related topic)
  • Examination review
Tagged under: Algorithm, Computer Programming, Conditional Statements, Game Development, Python, Tic Tac Toe
Home » Computer Programming » EITC/CP/PPF Python Programming Fundamentals » Advancing in Python » Calculating horizontal winner » Examination review » » How can we calculate the horizontal winner in a game of tic-tac-toe using a "not match" flag?

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