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I do not quite understand when the machine is in state q1 how it encounters an epsilon edge. Is it by definition?

by Mikael Kressner / Monday, 27 July 2026 / Published in Cybersecurity, EITC/IS/CCTF Computational Complexity Theory Fundamentals, Finite State Machines, Introduction to Nondeterministic Finite State Machines

The question concerns the operational semantics of nondeterministic finite automata (NFA) and, specifically, the concept of epsilon (ε) transitions—also known as epsilon edges or lambda transitions. Let us clarify how and why an NFA in a particular state, such as q1, may encounter and utilize an epsilon transition. This explanation will be grounded in the definitions and theoretical framework of automata theory.

Nondeterministic Finite Automata and Epsilon Transitions

A nondeterministic finite automaton (NFA) is a 5-tuple (Q, Σ, δ, q0, F), where:
– Q is the finite set of states,
– Σ is the finite input alphabet,
– δ: Q × (Σ ∪ {ε}) → 2^Q is the transition function,
– q0 ∈ Q is the initial state,
– F ⊆ Q is the set of accept states.

What differentiates an NFA from a deterministic finite automaton (DFA) is the nature of its transition function. For each state and input symbol, an NFA may transition to any subset of states (including the empty set), and it may also allow transitions on the empty string, ε. The ε transition enables the automaton to move from one state to another without consuming any input symbol.

Behavior of Epsilon Transitions

An epsilon transition is represented in the transition function as δ(q, ε). When the automaton is in a state q, if δ(q, ε) is nonempty, then the automaton, by definition, can move to all states in δ(q, ε) without reading (i.e., consuming) any symbol from the input string. This is a formal construct: whether or not an ε transition exists from a particular state is entirely determined by the definition of the NFA itself.

Encountering an Epsilon Transition

When the automaton is in state q1, the process for "encountering" an epsilon edge is governed by the transition function δ. If δ(q1, ε) is defined to include one or more states (say, δ(q1, ε) = {q2, q3}), then the automaton is permitted to transition from q1 to q2 and/or q3 spontaneously, without consuming any input symbol.

This is not a matter of chance or runtime discovery; it is a matter of how the state transitions have been defined in the automaton. The phrase "encountering an epsilon edge" means: as part of the automaton's execution (simulation), whenever the automaton is in state q1, it always has the *option* (permitted by the definition of δ) to follow the epsilon edge if such an edge exists.

Formally:

If the automaton A = (Q, Σ, δ, q0, F) is in state q1 at some step during the processing of an input string w, and δ(q1, ε) = S where S ⊆ Q and S ≠ ∅, then at this point, the automaton can *nondeterministically* transition to any of the states in S, without reading any further input symbols.

Why Epsilon Transitions Exist

Epsilon transitions are a feature of the model to increase expressive power and simplify automaton construction, particularly for certain regular language representations and constructions such as those arising from regular expressions, Thompson’s construction, and automata minimization techniques. They do not increase the class of languages recognizable by finite automata (since any NFA with epsilon transitions can be converted into an equivalent NFA without them, and then into a DFA), but they are a useful modeling tool.

Operational Semantics: Spontaneity and Nondeterminism

The operation of an NFA is inherently nondeterministic. At any step, if there are multiple possible transitions (including epsilon transitions), the automaton may "choose" any available transition. This means that the existence of an epsilon edge from q1 means that, at any point when the automaton is in q1, it may take that edge instantly, as a "spontaneous" move, without consuming input.

This is not dictated by an external event or runtime condition but is a property of the transition function δ as specified in the automaton’s definition.

Example

Consider an NFA defined as follows:

– Q = {q0, q1, q2}
– Σ = {a, b}
– δ is given by:
– δ(q0, a) = {q0}
– δ(q0, ε) = {q1}
– δ(q1, b) = {q2}
– δ(q2, a) = {q2}
– q0 is the initial state
– F = {q2}

Suppose the input string is "ba". The automaton operates as follows:

1. The automaton starts in q0.
2. In q0, before reading any input, the automaton may take the epsilon transition to q1 (δ(q0, ε) = {q1}). This is a *choice* available at every point the automaton is in q0, even before processing any input symbol.
3. If the automaton takes the epsilon transition to q1, it remains in q1, with the entire input "ba" still unconsumed.
4. In q1, the automaton may take the transition δ(q1, b) = {q2} if the first symbol of input is b. It consumes 'b', moving to q2 with remaining input 'a'.
5. In q2, δ(q2, a) = {q2}, so it can process 'a' and remain in q2.
6. q2 is an accepting state, and the whole input is consumed, so "ba" is accepted.

Alternatively, the automaton could have remained in q0 and attempted to process 'b' by δ(q0, b), but no such transition exists, so only the path involving the epsilon transition leads to acceptance.

Epsilon Closure

To formalize the behavior of epsilon transitions, the concept of epsilon-closure is introduced. The epsilon-closure of a state q, denoted as ε-closure(q), is the set of states reachable from q by traversing zero or more epsilon transitions (including q itself). When simulating an NFA, one always considers not just the current state but all states reachable via any sequence of epsilon transitions from the current state before consuming the next input symbol.

Computing Epsilon-Closure:

Given state q1, the epsilon-closure of q1 is the set of all states that can be reached from q1 by any sequence (including the empty sequence) of epsilon transitions. When the automaton is in q1, it is considered to be "in" all states within ε-closure(q1) simultaneously, for the purposes of processing the next input symbol.

For example, in the previous NFA:

– ε-closure(q0) = {q0, q1} (since q0 has an epsilon transition to q1)
– ε-closure(q1) = {q1} (since q1 has no epsilon transitions)
– ε-closure(q2) = {q2} (since q2 has no epsilon transitions)

So, when starting in q0, before any input is read, the automaton is considered to be in both q0 and q1. This means that, for the first input symbol, transitions from both q0 and q1 are possible.

Nondeterministic Computation and Acceptance

NFAs accept input strings if there exists *any* sequence of choices (including epsilon transitions) leading to an accepting state after the input is consumed. The presence of epsilon transitions increases the number of possible computation paths but does not change the definition of acceptance.

Theoretical Motivation

The reason that NFAs allow epsilon transitions is largely practical within theoretical computer science. When constructing automata corresponding to regular expressions, it is often natural to introduce epsilon transitions to represent concatenation, alternation, or optionality in a regular expression. For instance, when converting a regular expression such as "a(b|c)*d" into an automaton, epsilon transitions are used to glue together sub-automata for each component.

From the standpoint of computational complexity and automata theory, epsilon transitions do not increase the expressive power of the automaton model. For every NFA with epsilon transitions, there exists an equivalent NFA without epsilon transitions—this is achieved by computing the epsilon-closure of each state and modifying the transition function accordingly.

Practical Simulation

In terms of simulating or implementing an NFA, the process is as follows:

1. Compute the epsilon-closure of the initial state. The set of all states in the epsilon-closure is the set of "current" states.
2. For each input symbol, compute the set of states reachable from any current state via transitions labeled with the current input symbol.
3. For each such state, again compute its epsilon-closure and update the set of current states.
4. After all input symbols have been read, if any of the current states is an accepting state, the automaton accepts the input.

This process ensures that all possible sequences of epsilon transitions are correctly considered at every step.

Further Example

Consider the following NFA:

– Q = {q0, q1, q2}
– Σ = {a, b}
– δ:
– δ(q0, a) = {q1}
– δ(q1, ε) = {q2}
– δ(q2, b) = {q2}
– q0 is the initial state
– F = {q2}

Let us trace the input "ab":

1. Begin at q0. ε-closure(q0) = {q0}.
2. Read 'a'. δ(q0, a) = {q1}. ε-closure(q1) = {q1, q2} (since q1 has an epsilon transition to q2).
3. Now, current states after 'a' are {q1, q2}.
4. Read 'b'. δ(q1, b) = ∅ (since there is no transition from q1 on 'b'), δ(q2, b) = {q2}. ε-closure(q2) = {q2}.
5. After processing 'b', the only current state is q2, which is accepting.

This illustrates how, when processing input, epsilon transitions must be considered at every step—both before and after consuming an input symbol—by computing the epsilon-closure.

Is Epsilon Transition Encountered by Definition?

To address the original question succinctly: yes, the fact that the automaton in state q1 may "encounter" an epsilon edge is entirely by definition. The transition function δ specifies, for each state, which (if any) epsilon transitions are available. When the automaton is in state q1, the existence of an epsilon transition from q1 is specified by δ(q1, ε). There is no external or additional mechanism by which an epsilon edge is encountered; it is a direct consequence of the automaton's definition.

If δ(q1, ε) is nonempty, then the automaton has the *option* to follow an epsilon transition from q1 at any step, regardless of the input string or any other external condition. This is a formal property of the definition of the automaton, not an emergent behavior.

Summary Paragraph

Epsilon transitions in nondeterministic finite automata are a formal construct defined in the transition function of the automaton. When the automaton is in a given state, the existence and use of an epsilon transition are entirely prescribed by the automaton’s definition. The automaton may always take an epsilon transition from a state whenever such a transition is specified, independently of the input, and without consuming any symbol. This mechanism underpins the operational semantics of NFAs, facilitates certain automaton constructions, and is handled in simulation by computing epsilon-closures. The use of epsilon transitions is thus a direct consequence of the transition function's definition and does not arise from any process external to this formalism.

Other recent questions and answers regarding Introduction to Nondeterministic Finite State Machines:

  • How does nondeterminism impact transition function?
  • Can a Nondeterministic Finite Automaton (NFA) be used to represent the state transitions and actions in a firewall configuration?
  • When we have two or more acceptable paths in a non-deterministic machine, which one do we choose and what criteria can we use?
  • How can the concept of nondeterministic finite state machines be applied in the field of cybersecurity?
  • How can a string be accepted by a nondeterministic finite state machine?
  • What are epsilon edges in the context of nondeterministic finite state machines?
  • How do nondeterministic finite state machines handle multiple possible transitions from a given state on a given input symbol?
  • What is the main difference between deterministic and nondeterministic finite state machines?

More questions and answers:

  • Field: Cybersecurity
  • Programme: EITC/IS/CCTF Computational Complexity Theory Fundamentals (go to the certification programme)
  • Lesson: Finite State Machines (go to related lesson)
  • Topic: Introduction to Nondeterministic Finite State Machines (go to related topic)
Tagged under: Automata Theory, Cybersecurity, Epsilon Transition, Formal Languages, NFA, State Machines
Home » Cybersecurity » EITC/IS/CCTF Computational Complexity Theory Fundamentals » Finite State Machines » Introduction to Nondeterministic Finite State Machines » » I do not quite understand when the machine is in state q1 how it encounters an epsilon edge. Is it by definition?

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