In the field of computer networking, specifically in the realm of Internet protocols and IP addressing, the question at hand is whether a broadcast IP for the network, in which a device has the IP address 10.42.37.12/22, could be 10.42.39.255. To answer this question, we need to delve into the fundamentals of IP addressing, subnetting, and the concept of a broadcast address.
IP addressing is a crucial aspect of computer networking, as it allows devices to communicate with each other over a network. Each device connected to a network is assigned a unique IP address, which consists of a network portion and a host portion. The network portion identifies the network to which the device belongs, while the host portion identifies the specific device within that network.
In the given scenario, the device has an IP address of 10.42.37.12/22. The "/22" notation indicates that the first 22 bits of the IP address represent the network portion, leaving the remaining 10 bits for the host portion. By examining the IP address and the subnet mask, we can determine the network address and the range of valid host addresses.
To calculate the network address, we perform a bitwise AND operation between the IP address and the subnet mask. In this case, the subnet mask for a /22 network is 255.255.252.0, which in binary is 11111111.11111111.11111100.00000000. Performing the bitwise AND operation, we get:
IP address: 00001010.00101010.00100101.00001100
Subnet mask: 11111111.11111111.11111100.00000000
Network address: 00001010.00101010.00100100.00000000
Hence, the network address for the given IP address and subnet mask is 10.42.36.0.
Now, let's focus on the broadcast address. A broadcast address is a special address that allows a message to be sent to all devices on a network. It is obtained by setting all the host bits in the IP address to 1. In this case, since we have a /22 network, the host portion has 10 bits. Therefore, the broadcast address can be calculated as follows:
Network address: 00001010.00101010.00100100.00000000
Broadcast address: 00001010.00101010.00100111.11111111
Converting the binary representation back to decimal, we find that the broadcast address is 10.42.39.255.
Therefore, the answer to the question is yes, the broadcast IP for the network in which the device with the IP address 10.42.37.12/22 could indeed be 10.42.39.255. It falls within the range of valid broadcast addresses for the given network.
To summarize, the broadcast IP for a network with the IP address 10.42.37.12/22 can be 10.42.39.255. This conclusion is based on the understanding of IP addressing, subnetting, and the calculation of network and broadcast addresses.
Other recent questions and answers regarding EITC/IS/CNF Computer Networking Fundamentals:
- What are the limitations of Classic Spanning Tree (802.1d) and how do newer versions like Per VLAN Spanning Tree (PVST) and Rapid Spanning Tree (802.1w) address these limitations?
- What role do Bridge Protocol Data Units (BPDUs) and Topology Change Notifications (TCNs) play in network management with STP?
- Explain the process of selecting root ports, designated ports, and blocking ports in Spanning Tree Protocol (STP).
- How do switches determine the root bridge in a spanning tree topology?
- What is the primary purpose of Spanning Tree Protocol (STP) in network environments?
- How does understanding the fundamentals of STP empower network administrators to design and manage resilient and efficient networks?
- Why is STP considered crucial in optimizing network performance in complex network topologies with multiple interconnected switches?
- How does STP strategically disable redundant links to create a loop-free network topology?
- What is the role of STP in maintaining network stability and preventing broadcast storms in a network?
- How does Spanning Tree Protocol (STP) contribute to preventing network loops in Ethernet networks?
View more questions and answers in EITC/IS/CNF Computer Networking Fundamentals